若|2x+y-3|与(y-2)²互为相反数,求4x²y-3xy的值?

若|2x+y-3|与(y-2)²互为相反数,求4x²y-3xy的值?

答：
|2x+y-3|与(y-2)²互为相反数,则有：
|2x+y-3|+(y-2)²=0
所以：
2x+y-3=0
y-2=0
解得：y=2,x=1/2
所以：
4x²y-3xy
=xy(4x-3)
=4x-3
=2-3
=-1