(x²+6x+9)÷(x+3)(x²-3x)

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(x²+6x+9)÷(x+3)(x²-3x)

(x²+6x+9)÷(x+3)(x²-3x)
= (x+3)²÷(x+3)*x(x-3)
= (x+3)*x(x-3)
=x(x²-9)
= x³-9x

x三次-9x