计算4tan²π/4-cos²π/3-1/2sin²π/6+sinπ/2*cos0的值

计算4tan²π/4-cos²π/3-1/2sin²π/6+sinπ/2*cos0的值

原式=4×1²-(1/2)²-1/2×(1/2)²+1×1
=4-1/4-1/8+1
=37/8

不知道你这个是弧度还是角度
角度答案是 4*0-0/3-1/2/6+1/2=5/12