已知121(x-1)^2=36,y^3 +8=0,求(1)x-y的值(2)x^y的值

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已知121(x-1)^2=36,y^3 +8=0,求
(1)x-y的值
(2)x^y的值

121(x-1)^2=36
11(x-1)=6
x-1=6/11
x=17/11
y^3 +8=0
y^3=-8
y=-2
x-y=17/11+2=39/11
x+y=17/11-2=5/11

121(x-1)^2=36
11(x-1)=6
x-1=6/11
x=17/11
y^3 +8=0
y^3=-8
y=-2
x-y=17/11+2=39/11
x+y=17/11-2=5/11