若｜x+y-3｜+（x-y+5）²,则xy=

若｜x+y-3｜+（x-y+5）²,则xy=

即
/x+y-3/+(x-y+5)²=0吧
∵/x+y-3/≥0
(x-y+5)²≥0
∴x+y-3=0
x-y+5=0
两式相加
∴x=-1,y=4
∴xy=-1×4=-4

x+y-3=0
x-y+5=0

x=-1
y=4

xy=-1*4=-4

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