计算:x³/(x+1)-x²+x-1(x+1)分之x的立方 减x的平方 加x 减1

来源:学生作业学帮网 编辑:学帮网 时间:2024/06/06 15:17:38

计算:x³/(x+1)-x²+x-1
(x+1)分之x的立方 减x的平方 加x 减1

原式=x³/(x+1)-(x²-x+1)
=x³/(x+1)-(x+1)(x²-x+1)/(x+1)
=[x³-(x+1)(x²-x+1)]/(x+1)
=[x³-(x³+1)]/(x+1)
=-1/(x+1)

x等于二分之一

原式=x³/(x+1)-(x²-x+1)
=x³/(x+1)-(x+1)(x²-x+1)/(x+1)
=[x³-(x+1)(x²-x+1)]/(x+1)
=[x³-(x³+1)]/(x+1)
=-1/(x+1)