若sinx-sin(3/2π-x)=根号2,则tanx+tan(3/2π-x)的值是?若sinx-sin((3/2)π-x)=根号2,则tanx+tan((3/2)π-x)的值是

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若sinx-sin(3/2π-x)=根号2,则tanx+tan(3/2π-x)的值是?
若sinx-sin((3/2)π-x)=根号2,则tanx+tan((3/2)π-x)的值是

sinx-sin(3π/2-x)=sinx+cosx=√2
平方
sin²x+cos²x+2sinxcosx=2
1+2sinxcosx=2
sinxcosx=1/2
原式=tanx+cotx
=sinx/cosx+cosx/sinx
=(sin²x+cos²x)/sinxcosx
=1/(1/2)
=2

原式={[(a²+b²)-(a-b)²]/(a+b)(a-b)}[(a-b)/a2b]
=[(a²+b²-a²+2ab-b²)(a-b)]/[2ab(a+b)(a-b)]
=2ab/[2ab(a+b)]
=1/(a+b) 原式={[(a²+b²)-(a-b)²]/(a+b)(a-b)}[(a-b)/a2b]
=[(a²+b²-a²+2ab-b²)(a-b)]/[2ab(a+b)(a-b)]
=2ab/[2ab(a+b)]
=1/(a+b)