已知x,y满足x(+1)-(x²+2y)=1,求x²+4xy+4y²-2x+4y的值.抱歉，是x(x+1)-(x²+2y)=1

已知x,y满足x(+1)-(x²+2y)=1,求x²+4xy+4y²-2x+4y的值.
抱歉，是x(x+1)-(x²+2y)=1

x(x+1)-(x^2+2y)=1 => x-2y=1
(x-2y-1)^2 = (x-2y)^2 -2(x-2y) +1 = x^2 -4xy + 4y^2 -2x+4y +1 =0
所以x^2 -4xy + 4y^2 -2x+4y =-1