先化简再求值x-y分之1-x+y分之1除以x²-y²分之xy²,其中x=√2+1,y=√2-1

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先化简再求值x-y分之1-x+y分之1除以x²-y²分之xy²,其中x=√2+1,y=√2-1

x-y分之1-x+y分之1除以x²-y²分之xy²
=[(x+y-x+y)/(x²-y²)]÷xy²/(x²-y²)
=2y/(x²-y²)*(x²-y²/xy²
=2/xy 其中x=√2+1,y=√2-1
=2/[(√2+1)(√2-1)]
=2/(2-1)
=2

=2