(1)计算:(2+1)(2^2+1)(2^4+1)……(2^32+1) (2) 试求(1)中结果的个位数字

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(1)计算:(2+1)(2^2+1)(2^4+1)……(2^32+1) (2) 试求(1)中结果的个位数字

(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
= (2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
= ...
= 2^64-1