已知集合A={（x,y)/(y-2)÷(x-1)=a+2},B={(x,y)/(a^2-4)x+(a-2)=16},若对于x,y∈R,A∩B=空集,求a的值

已知集合A={（x,y)/(y-2)÷(x-1)=a+2},B={(x,y)/(a^2-4)x+(a-2)=16},若对于x,y∈R,A∩B=空集,求a的值

对于x,y∈R,A∩B=空集
=>
x无解或x=1
x无解
aa-4=0
a=2,-2
x=1
=>
aa+a-22=0
=>
a=(-1+√89)/2,(-1-√89)/2