若/x+3/+/y-2/+/2z+1/=0,求(xy-yz)(y-x+z)的值

来源:学生作业学帮网 编辑:学帮网 时间:2024/05/30 22:50:32

若/x+3/+/y-2/+/2z+1/=0,求(xy-yz)(y-x+z)的值

/x+3/+/y-2/+/2z+1/=0
所以x+3=y-2=2z+1=0
X=-3
Y=2
Z=-0.5
得出:(xy-yz)=(-3*2)-(2*-0.5)=-5
(y-x+z)=2-(-3)+(-.05)=4.5