若实数x y满足(x+y)²+(x+y)-2=0则x+y值为
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若实数x y满足(x+y)²+(x+y)-2=0则x+y值为
(x+y)²+(x+y)-2=0
(x+y+2)(x+y-1)=0
x+y=-2或x+y=1
(x+y)²+(x+y)-2=0
(x+y+2)(x+y-1)=0
x+y=-2或x+y=1
把X+Y看成T
(x+y)²+(x+y)-2=0
(x+y+2)(x+y-1)=0
所以x+y=-2,x+y=1