f(x)=sin(wx+pai/6)-1(w>0)求f'(x)

f(x)=sin(wx+pai/6)-1(w>0)
求f'(x)

这么简单?这是一个复合函数,先求外层函数sin(wx+pai/6)-1的导,然后再求内层函数（wx+pai/6）,最后相乘,结果为wcos(wx+pai/6)

f(x) = sin(wx + π/6) - 1
f'(x) = wcos(wx + π/6)

f'(x)=wcos(wx+pai/6)