.先化简,后计算.[2x(x²y-xy²)+xy(xy-x²)]/x²yx=2008,y=2004

.先化简,后计算.
[2x(x²y-xy²)+xy(xy-x²)]/x²y
x=2008,y=2004

[2x(x²y-xy²)+xy(xy-x²)]/x²y
=[2x^3y-2x^2y^2+x^2y^2-x^3y]/x²y
=x-y
=4

[2x(x2y-xy2)+xy(xy-x2)]/x2y=[2x*(xy)*(x-y)+x*xy(y-x)]/(x*xy)=xy*x*(x-y)/(x*xy)=x-y=4

[2x(x2y-xy2)+xy(xy-x2)]/x2y
=[2x*x*y(x-y)+x*x*y(y-x)]/x2y
=x*x*y*[2(x-y)+(y-x)]/x2y
=2(x-y)+(y-x)
=x-y
=4