已知.1/a-1/b=5,求(2a+3ab-2b)/(a-2ab-b)的值.

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1/a-1/b=5
(b-a)/ab=5
b-a=5ab
a-b=-5ab
(2a+3ab-2b)/(a-2ab-b)
=[2(a-b)+3ab]/[(a-b)-2ab]
=(-10ab+3ab)/(-5ab-2ab)
=(-7ab)/(-7ab)
=1