已知长方形ABCD中,AD=6cm,AB=4cm,点E为AD的中点,若点P在线段AB上以1cm/s的速度由点A向点B运动,同时,点Q在线段BC上由点B向点C运动.1、若点Q的运动速度与点P的运动速度相等,经过1秒后,三角形AEP与三

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已知长方形ABCD中,AD=6cm,AB=4cm,点E为AD的中点,若点P在线段AB上以1cm/s的速度由点A向点B运动,同时,点Q在线段BC上由点B向点C运动.
1、若点Q的运动速度与点P的运动速度相等,经过1秒后,三角形AEP与三角形BPQ是否全等,请说明理由,并判断此时线段PE与线段PQ的位置关系.
2、若点Q的运动速度与点P的运动速度相等,运动时间为t 秒,设三角形PEQ的面积为
Scm²,请用t的代数式表示S
3、若点Q的运动速度与点P的运动速度不相等,当点Q的运动速度为多少时,能够使三角形AEP与三角形BPQ全等

1、三角形AEP与三角形BPQ全等,原因：三角形AEP与三角形BPQ是直角三角形,且AP=BQ=1cm,AE=BP=3cm,所以全等.线段PE和线段PQ是垂直关系.
2、S=t*t/2-3*t/2+6.用直角梯形AEQB的面积减去直角三角形AEP的面积和直角三角形BPQ的面积
3、由1已知点Q速度为1cm/s时满足条件,这种情况是AP=BQ,AE=BP；换另外一种情况则是使AP=BP,AE=BQ,设点Q的速度为v,可列方程t=4-t和vt=3,解得t-2s,v=1.5cm/s.

1.三角形AEP与三角形全等。AE=3cm，AP=1cm，BP=3CM，BQ=1CM,三角形AEP与三角形BPQ是直角三角形，所以三角形AEP与三角形BPQ全等。此时PE垂直于PQ.
2.S=(9+t平方)/2
3.由1已知点Q速度为1cm/s时满足条件，这种情况是AP=BQ，AE=BP；换另外一种情况则是使AP=BP,AE=BQ，设点Q的速度为v，可列方程t=4-t和vt=3，解...

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after the car hit a pedestrian escape ,mercurial vapor, followed with four cars collided , causing two deaths and two injuries, Mercedes-Benz car hit the tree burned down , the Li Shilan surrendered ( January 20,nike mercurial vapor, newspaper reports ) .

process for the incident , Li Shilan said at his trial fell asleep while driving , to be greeted by a large truck , the lights blink of an eye , could not find the brake . After the incident,scarpe nike mercurial, Li Shilan paid 120 million yuan compensation from the victims .

court that Li Shilan in the event of the first car to escape after the accident , and in the process of driving the escape car crash more cars , causing two deaths and two minor injuries , constituted the crime of endangering public safety . In view of its initiative to surrender after the crime , and actively damages , therefore lighter made ??the above decision.

After the verdict , Li Shilan stretch appeal .

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