求[(a²+b²)+2b(a-b)-(a-b)²]÷4b的值(已知2a-b=5)

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求[(a²+b²)+2b(a-b)-(a-b)²]÷4b的值(已知2a-b=5)

[(a²+b²)+2b(a-b)-(a-b)²]÷4b
=[a²+b²+2ab-2b²-(a²-2ab+b²)]÷4b
=[4ab-2b²]÷4b
=(2a-b)除以2
=5/2

[(a²+b²)+2b(a-b)-(a-b)²]÷4b
=[2ab+2b(a-b)]÷4b
=2b(2a-b)÷4b
=5/2