x:y=3:2,y:z=5:4,x+y+z=66的解的过程?

来源：学生作业学帮网编辑：学帮网时间：2024/05/05 20:14:03

由x:y=3:2 得 x:y=15:10
由y:z=5:4 得 y:z=10:8
∴ X:Y:Z=15:10:8
即 X:15=Y:10=Z:8
若 X:15=Y:10=Z:8=k
则 X=15k Y=10k Z=8k
又∵x+y+z=66
∴15k+10k+8k=66
∴k=2
∴X=30 Y=20 Z=16

晕 X:Y:Z=15:10:8 你把X Y都换成Z就可以了

解: 由x:y=3:2,y:z=5:4,得x=(3/2)y...... (1), z=(4/5)y.......(2)
把x=(3/2)y,z=(4/5)y.代入x+y+z=66得,(3/2)y+y+(4/5)y=66,y=20
再把y=20分别代入(1),(2)得 x=30,z=16.
所以原方程组的解为 x=30, y=20,z=16.

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