cosπ/7cos2π/7cos4π/7=?写下过程,谢谢~

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cosπ/7cos2π/7cos4π/7=?
写下过程,谢谢~

(sinπ/7cosπ/7cos2π/7cos4π/7)/sinπ/7=(0.5sin2π/7cos2π/7cos4π/7)/sinπ/7=(0.25sin4π/7cos4π/7)/sinπ/7=(0.125sin8π/7)/sinπ/7=(-0.125sinπ/7)/sinπ/7=-1/8