求sin(2x+6/π）的单调递增,递减区间

求sin(2x+6/π）的单调递增,递减区间

正弦函数在[-π/2+2kπ,π/2+2kπ],k∈Z上是单调增函数,在[π/2+2kπ,3π/2+2kπ],k∈Z上是单调减函数,所以
增区间：-π/2+2kπ<=2x+6/π<=π/2+2kπ
减区间：π/2+2kπ<=2x+6/π<=3π/2+2kπ
解得
增区间：[-π/3+kπ,π/6+kπ]
减区间：[π/6+kπ,2π/3+kπ]