{3x-2y+2z=10 ,x-5y+2z=13 ,7x+y-2z=-9 解3元1次方程

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3x-2y+2z=10.(1)
x-5y+2z=13.(2)
7x+y-2z=-9.(3)
(1)+(3)得
10x-y=1.(4)
(2)+(3)得
8x-4y=4
即2x-y=1.(5)
(4)-(5)得
8x=0
x=0
代入(5)得
-y=1
y=-1
把x=0,y=-1代入(1)得
2+2z=10
z=4
解得
x=0
y=-1
z=4

3x-2y+2z=10 ........................1
x-5y+2z=13 ......................2
7x+y-2z=-9 .....................3
1式+3式得
10x-y=1...................4
2式+3式得
8x-4y=4
2x-y=1............

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3x-2y+2z=10 ........................1
x-5y+2z=13 ......................2
7x+y-2z=-9 .....................3
1式+3式得
10x-y=1...................4
2式+3式得
8x-4y=4
2x-y=1...................5
4式-5式得
8x=0
x=0................6
将6式代入4式得
10*0-y=1
y=-1...................7
将6式，7式代入1式得
3*0-2*(-1)+2z=10
2+2z=10
2z=8
z=4
所以x=0,y=-1,z=4

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