「(2x-y)^2+y(x-y)」÷8x「4x(x-1)^2-x(2x+3)(2x-3)」÷4x

来源:学生作业学帮网 编辑:学帮网 时间:2024/05/19 16:17:07

「(2x-y)^2+y(x-y)」÷8x
「4x(x-1)^2-x(2x+3)(2x-3)」÷4x

(1)
「(2x-y)^2+y(x-y)」÷8x
=(4x^2-4xy+y^2+xy-y^2)/8x
=x/2-3y/8
(2)
「4x(x-1)^2-x(2x+3)(2x-3)」÷4x
=(4x^2-4x-4x^3+9x)/4x
=-x^2+x+5/4

1.
「(2x-y)^2+y(x-y)」÷8x
=[4x^2-4xy+y^2+xy-y^2]÷8x
=(4x^2-3xy)÷8x
=1/2x-3/8y
2.「4x(x-1)^2-x(2x+3)(2x-3)」÷4x
=[4x(x^2-2x+1)-x(4x^2-9)]÷4x
=[13x-8x^2]÷4x
=5/4x