(x-1/2y-1)(x-1/2y+1)-(x-1/2y+1)^2,其中x=1.5,y=3.9,先化简再求值过程详细,请各位大神帮帮忙
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(x-1/2y-1)(x-1/2y+1)-(x-1/2y+1)^2,其中x=1.5,y=3.9,先化简再求值
过程详细,请各位大神帮帮忙
(x-1/2y-1)(x-1/2y+1)-(x-1/2y+1)²
=(x-1/2y)²-1²-(x-1/2y+1)²
=(X-1/2y)²-1-[(x-1/2y)²+2(x-1/2y)+1]
=(X-1/2y)²-1-(x-1/2y)²-2(x-1/2y)-1
=-2-2(x-1/2y)
=-2-2x+y
把数值代入得:
原式=-2-2*(1.5)+3.9
=-2-3+3.9
=-2+0.9
=-1.1
1.2乘8.52
原式=[(x-1/2y)-1][(x-1/2y)+1]-[(x-1/2y)+1]²
=(x-1/2y)²-1²-(x-1/2y)²-2(x-1/2y)-1
=2(x-1/2y)-2
=2x-y-2
=2*1.5-3.9-2
=-2.9(x-1/2y)²-2(x-1/2y)-1,这个不可以这样拆吧,貌似不对的感...
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原式=[(x-1/2y)-1][(x-1/2y)+1]-[(x-1/2y)+1]²
=(x-1/2y)²-1²-(x-1/2y)²-2(x-1/2y)-1
=2(x-1/2y)-2
=2x-y-2
=2*1.5-3.9-2
=-2.9
收起
提取公因式(x-y/2+1)[(x-y/2-1)-(x-y/2+1)]=-2(x-y/2+1)=-2(1.5-3.9/2+1)=-5+3.9=-1.1
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