y=-2x²-3x+1配方
来源:学生作业学帮网 编辑:学帮网 时间:2024/05/30 06:48:48
y=-2x²-3x+1配方
y=-2x²-3x+1
=-2(x²-3x/2)+1
=-2[x²-3x/2+(3/4)²]+2×(3/4)²+1
=-2(x-3/4)²+17/8
y=-2x²-3x+1
=-2(x²+3x/2-1/2)
=-2[x²+2*3/4*x+(3/4)²-(3/4)²-1/2]
=-2[(x+3/4)²-17/16]
=-2(x+3/4)²+17/8
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来源:学生作业学帮网 编辑:学帮网 时间:2024/05/30 06:48:48
y=-2x²-3x+1配方
y=-2x²-3x+1
=-2(x²-3x/2)+1
=-2[x²-3x/2+(3/4)²]+2×(3/4)²+1
=-2(x-3/4)²+17/8
y=-2x²-3x+1
=-2(x²+3x/2-1/2)
=-2[x²+2*3/4*x+(3/4)²-(3/4)²-1/2]
=-2[(x+3/4)²-17/16]
=-2(x+3/4)²+17/8