NO.1 (log3 2 + log9 2) (log4 3 + log8 3) NO.2 (lg5)的平方 + (lg50 乘 lg2)NO.3 [(1 - log6 3)的平方 + (log6 2 乘 log6 18)] 除 log6 4第一题你做错了,是5/4
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NO.1 (log3 2 + log9 2) (log4 3 + log8 3)
NO.2 (lg5)的平方 + (lg50 乘 lg2)
NO.3
[(1 - log6 3)的平方 + (log6 2 乘 log6 18)] 除 log6 4
第一题你做错了,是5/4
1.原式
=(log3(2)+1/2log3(2))*(2log2(3)+3log2(3))
=3/2*5*log2(3)*log3(2)
=15/2
2.因为(lg5)^2+lg2*lg50
=(lg5)^2+lg2*lg(5*10)
=(lg5)^2+lg2*(lg5+lg10)
=(lg5)^2+lg2(lg5+1)
=lg5*(lg2+lg5)+lg2
=lg5*lg10+lg2
=lg5+lg2=lg(2*5)=lg10=1
3.[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)
=[log6(2)^2 + log6(2) × (log6(3)+1)]÷2log6(2)
=(log6(2)+log6(3)+1)/2
=(1+1)/2
=1
log3*2/log9*4
log3 5-log3 15+1/2log9 27 的值
log3*2/log9*4=?
|log3(5)-2|+log9(25)+(1/32)^1/5
化简:log2 2+log5 1-3^(2log9 5)+(3log3 5)^2+3^log3 2
(log3 2)+log9 2)*(log4 3+log8 3)+(log3 3^1/2)^2+ln根号e-lg1
log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=
-5log9 4+log3 32/9-5^log5 3-(1/64)^-2/3
计算:-5log9^4+log3^32/9-5log5^3-(1/64)^-2/3
log3(x2)+log9(1/x)+3/2=0怎么解
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