计算①9√1/45÷3/2√3/5×1/2√2﹙2/3﹚√6-1②﹙/3√√3/2-1/2√24﹚×﹙-2√6﹚③√8/3+√1/2+√0.125-√6+√32④﹙3-√2﹚²﹙3+√2﹚+﹙3+√2﹚²﹙3-√2﹚

来源:学生作业学帮网 编辑:学帮网 时间:2024/06/04 23:38:34

计算①9√1/45÷3/2√3/5×1/2√2﹙2/3﹚
√6-1②﹙/3√√3/2-1/2√24﹚×﹙-2√6﹚③√8/3+√1/2+√0.125-√6+√32④﹙3-√2﹚²﹙3+√2﹚+﹙3+√2﹚²﹙3-√2﹚

=-2√6^2-1/3√3/2*(-2√6)-1/2√24*(-2√6)
=-12+2/3√3/2*6+√24*6
=-12+2/3√9+√24*6
=-12+2/3*3+12
=2