奇偶性f(x)=cos(π/2+2x)cos(π+x)

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f(x)
=cos(π/2+2x)cos(π+x)
=-sin(2x)[-cos(x)]
=2sinxcos²x
f(0)=0
f(-x)=2sin(-x)cos²(-x)=-2sinxcos²x=-f(x)
f(x)是奇函数