复数1+i/4+3i的虚部是?
复数1+i/4+3i的虚部是?
1+i/4+3i
=(1+i)(4-3i)/(4+3i)(4-3i)
=(7+i)/25
=7/25+(1/25)i
虚部是1/25
1+i/4+3i
=1+(1/4+3)i
=1+13/4i
因此虚数部是13/4
复数1+i/4+3i的虚部是?
1+i/4+3i
=(1+i)(4-3i)/(4+3i)(4-3i)
=(7+i)/25
=7/25+(1/25)i
虚部是1/25
1+i/4+3i
=1+(1/4+3)i
=1+13/4i
因此虚数部是13/4