已知n为正整数,且1/(1+n)+1/(3+n)+1/(6+n)>19/36,求N的最小值
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已知n为正整数,且1/(1+n)+1/(3+n)+1/(6+n)>19/36,求N的最小值
19/36=1/(1+3 )+1/(3+3)+1/(6+3)
1/(1+n )+1/(3+n)+1/(6+n)>1/(1+3 )+1/(3+3)+1/(6+3)
n
已知n为正整数,且1/(1+n)+1/(3+n)+1/(6+n)>19/36,求N的最小值
19/36=1/(1+3 )+1/(3+3)+1/(6+3)
1/(1+n )+1/(3+n)+1/(6+n)>1/(1+3 )+1/(3+3)+1/(6+3)
n