(2/3)^0+(√8)*(0.25)^(1/4)-lg25-2lg2
来源：学生学帮网 编辑：学帮网 时间：2024/06/17 04:37:39
(2/3)^0+(√8)*(0.25)^(1/4)-lg25-2lg2
原式=1+(√8)*【(0.5)^2】^(1/4)-（lg25+lg4)
=1+√8*√0.5-lg100
=1+√4-2
=1+2-2
=1
(2/3)^0+(√8)*(0.25)^(1/4)-lg25-2lg2
原式=1+(√8)*【(0.5)^2】^(1/4)-（lg25+lg4)
=1+√8*√0.5-lg100
=1+√4-2
=1+2-2
=1