求帮忙做2道大一高数题
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求帮忙做2道大一高数题
∫xacrtanxdx
=∫arctanxd(x²/2)
=arctanx*x²/2-∫x²/2(1+x²)dx
=arctanx*x²/2-∫[1/2 -1/2(1+x²)]dx
=arctanx*x²/2-x/2+arctanx /2
=[(x²+1)arctanx-x]/2
求帮忙做2道大一高数题
∫xacrtanxdx
=∫arctanxd(x²/2)
=arctanx*x²/2-∫x²/2(1+x²)dx
=arctanx*x²/2-∫[1/2 -1/2(1+x²)]dx
=arctanx*x²/2-x/2+arctanx /2
=[(x²+1)arctanx-x]/2