先化简,再求值:(1+1\x-1)除以x\x^2-1,其中x=2.
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先化简,再求值:(1+1\x-1)除以x\x^2-1,其中x=2.
(1+1\x-1)除以x\x^2-1,
=(x-1+1)/(x-1) × (x+1)(x-1)/x
=x+1
=2+1
=3
先化简,再求值:(1+1\x-1)除以x\x^2-1,其中x=2.
(1+1\x-1)除以x\x^2-1,
=(x-1+1)/(x-1) × (x+1)(x-1)/x
=x+1
=2+1
=3