若(3x-y-6)²+2x+y-4绝对值=0,则x= ,y= .

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若(3x-y-6)²+2x+y-4绝对值=0,则x= ,y= .

(3x-y-6)²+2x+y-4绝对值=0
3x-y-6=0
2x+y-4=0
5x-10=0
x=2
6-y-6=0
y=0
x=2
y=0

(3x-y-6)²+2x+y-4绝对值=0,
所以3x-y-6=0 2x+y-4=0
解得：x=2 y=0