戴维宁定理求电流I
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戴维宁定理求电流I
I1 = (20 -10) / (6+4) = 1 A
Uab = -7 + 10 + 6 * 1 = 9 V
Rab = 6//4 = 2.4 Ω
I = Uab / (Rab + 12.6) = 9 / 15 = 0.6 A
戴维宁定理求电流I
I1 = (20 -10) / (6+4) = 1 A
Uab = -7 + 10 + 6 * 1 = 9 V
Rab = 6//4 = 2.4 Ω
I = Uab / (Rab + 12.6) = 9 / 15 = 0.6 A