设函数f(x)={(1/2)^x(x≥4),f(x+3)(x
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设函数f(x)={(1/2)^x(x≥4),f(x+3)(x
f(x)={(1/2)^x(x≥4),f(x+3)(x<4)
∵1<log(2)3<2 , 3+log(2)3>4
∴f(log(2)3)=f[3+log(2)3]=f[log(2)24]
=(1/2) ^log(2)24
=1/2^log(2)24
=1/24
设函数f(x)={(1/2)^x(x≥4),f(x+3)(x
f(x)={(1/2)^x(x≥4),f(x+3)(x<4)
∵1<log(2)3<2 , 3+log(2)3>4
∴f(log(2)3)=f[3+log(2)3]=f[log(2)24]
=(1/2) ^log(2)24
=1/2^log(2)24
=1/24