(4m^2-9n^2)/(2m-3n)是多少
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(4m^2-9n^2)/(2m-3n)是多少
(4m^2-9n^2)/(2m-3n)
=(2m-3n)(2m+3n)/(2m-3n)
=2n+3m
2m+3n
28/37
答案是2m+3n
因为
(4m^2-9n^2)=(2m)^2-(3n)^2=(2m+3n)(2m-3n)，
所以相除后就为以上结果
(4m^2-9n^2)/(2m-3n)是多少
(4m^2-9n^2)/(2m-3n)
=(2m-3n)(2m+3n)/(2m-3n)
=2n+3m
2m+3n
28/37
答案是2m+3n
因为
(4m^2-9n^2)=(2m)^2-(3n)^2=(2m+3n)(2m-3n)，
所以相除后就为以上结果