x2+y2-x2y2-4xy

x2+y2-x2y2-4xy-1x²+y²-x²y²-4xy-1=(x²-2xy+y²)-(x²y²+2xy+1)=(x+y)²-(xy+1)

x2y2-x2-y2+4xy+1分解因式x2y2-x2-y2+4xy+1=(xy)^2+2xy+1-(x^2-2xy+y^2)=(xy+1)^2-(x-y)^2=(xy+1+x-y)(xy+1-x+y)

(x2+y2)(x2-xy+y2)-2x2y2因式分解打开,然后再整理,就可以了~(x2+y2)(x2-xy+y2)-2x2y2=x4-x3y+2x2y2-xy3+y4-2x2y2=x4+y4-x3y-xy3=(x-y)(x3-y3)=(x

已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2=巳知是：(x-2y)的平方+(xy-1)的平方=0,利用非负数的性质得x=2y,且xy=1故y=±√2/2

(x2+y2)2-4x2y2因式分解(x2+y2)2-4x2y2因式分解=（x²+y²+2xy）(x²+y²-2xy)=(x+y)²(x-y)²如果本题有什么不明白可以追问,(x2

因式分解(x2+y2-a2)2-4x2y2(x2+y2-a2)2-4x2y2=（x²+y²-a²+2xy）(x²+y²-a²-2xy)=[(x+y)²-a²][

4x2y2-(x2+y2)2的答案4x2y2-(x2+y2)2=（2xy-x²-y²）（2xy＋x²+y²）=-(x-y)²(x+y)²4x²y²-（x

因式分解,x4-7x2y2+y4=?x4-7x2y2+y4=?应该是(x2+?xy+y2)(x2-?xy+y2)的形式,那个?是多少x4-7x2y2+y4=x4+2x^2y^2+y4-9x^2y^2=(x^2+y^2)^2--9x^2y^2

已知:x-y=-2求(x2+y2)2-4xy(x2+y2)+4x2y2的值(x2+y2)2-4xy(x2+y2)+4x2y2=(x^2+y^2-2xy)^2=(x-y)^4=(-2)^4=16

因式分解x2＋y2－x2y2－4xy－1；x²+y²-x²y²-4xy-1=(x²+y²-2xy)-(x²y²+2xy+1)=(x-y)²-(xy+1

已知x2+4y2+x2y2-6xy+1=0,求x4-y4/2x-y乘2xy-y2/xy-y2除以（x2+y2/xy）2乘1/x+y的值因为x²+4y²+x²y²-6xy+1=0(x²-4xy

分解因式(x2+y2)(x2-2xy+y2)+x2y2注；2为平方(x²+y²)(x²-2xy+y²)+x²y²=(x²+y²)²-2xy(x

因式分解x2y2-x2-y2+1原式=4xy-2x-2y+1=2x(2y-1)-(2y-1)=(2x-1)(2y-1)=X2y2-X2-y2+1=X2(y2-1)-(y2-1)=(y2-1)(x2-1)

X2y2-x2-y2+1因式分解.x^2(y^2-1)-(y^2-1)=(x^2-1)(y^2-1)=(x+1)(x-1)(y+1)(y-1)x^2y^2-x^2-y^2+1=x^2(y^2-1)-(y^2-1)=(x^2-1)(y^2-1

若实数x,y满足x2+y2+x2y2-4xy+1=0,则(x+y)2的值为原式化成x²-2xy+y²+x²y²-2xy+1=0即（x-y）²+（xy-1）²=0因为（x-y）

(x2+xy+y2)-4xy(x2+y2)想疯了!乱做后得出2(x+y)(1-4xy)+xy只要2分,不必理睬

(x2+y2-1)-4x2y2因式分解2是平方﹙x²＋y²－1﹚²－4x²y²＝﹙x²＋y²－1－2xy﹚﹙x²＋y²－1＋2xy﹚＝﹙x－y－1﹚﹙

分解因式(X2+Y2)2-4X2Y22是平方(x2+y2+2xy)(x2+y2-2xy)=(x+y)2(x-Y)2=(x2-y2)2=x4+y4-2x4y4

设x2y2-20xy+x2+y2+81=0,求x+y的值x2y2-20xy+x2+y2+81=0x2y2-18xy+81+x2-2xy+y2=0(XY-9)的平方+(X-Y)=0XY-9=0X-Y=0第一种X=-3Y=-3所以x+y=-3-

x2y2+xy-x2-y2＋x＋y＋2分解因式,原式=(x²y²-x²-y²+1)+(xy+x+y+1)=[x²(y²-1)-(y²-1)]+[x(y+1)+(y+1)]