sin(x+π2)

sin平方x-sinxcosx-2cos平方x求sin(x-π/3)X为锐角sin平方x-sinxcosx-2cos平方x=0求sin(x-π/3)请看图片

sin^2(π/3-x)+sin^2(π/6+x)解sin²(π/3-x)+sin²(π/6+x)=sin²[π/2-(π/6+x)]+sin²(π/6+x)=cos²(π/6+x)+sin

2sin(x+π/4)sin(x-π/4)=?2sin(x+π/4)sin(x-π/4)=2sin(x+π/4)sin[-π/2+(π/4+x)]=-2sin(x+π/4)cos(π/4+x)=-sin(2x+π/2)=-cos2x2sin

sin^2(π/4+x)sin^2(π/4+x)=[1-cos2(π/4+x)]/2=[1-cos(π/2+2x)]/2=1/2+sin2x/2运用公式Cos2A=CosA^2-SinA^2=1-2SinA^2sin^2(π/4+x)=[1

sin(πx/2)求导y=sin(πx/2)则y'=cos(πx/2)*(πx/2)'=π/2*cos(πx/2)

化简sin²x+sin²(x+2π/3)+sin²(x-2π/3)sin²x+sin²(x+2π/3)+sin²(x-2π/3) 

已知tanx=3,则[sin(π+x)-2sin(π/2+x)]/[sin(7π-x)+sin(7π/2-x)]已知tanx=3,则[sin(π+x)-2sin(π/2+x)]/[sin(7π-x)+sin(7π/2-x)]的值是tanx=

sin(x^2)/sin^2x求导y=sin(x^2)/(sinx)^2y'=2xcos(x^2)/(sinx)^2+sin(x^2)*(-sin2x)/(sinx)^3=【2xcos(x^2)(sinx)+sin(x^2)*(-sin2x

已知sin(π/2-x)+sin(π-x)/cos(-x)+sin(2π-x)=2009,则tan(x+5π/4)等于?已知sin(π/2-x)+sin(π-x)/cos(-x)+sin(2π-x)=2009,则tan(x+5π/4)等于（

已知函数f(x)=sin^2x+2根号3sinxcosx+sin(x+π/4)sin(x-π/4),x属于R,求f(x)的最小正周期和值域若x=x00≤x0小于等于π/2为f(x)的一个零点,求sin2x0的值f(x)=sin^2x+2√3

f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题,f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)=（sinx＋cosx）sinx＋cos（（x+π/4）＋(x-π

已知函数f(x)=(1+1\tanx)sin^2x+msin(x+π/4)sin(x-π/4)sin(x+π/4)sin(x-π/4)=[cos(π/2)-cos(2x)]/2=-cos(2x)/2(1+1\tanx)sin^2x=[(si

已知-π/2＜x＜0,sinx+cosx=1/5求sin2x+2sin已知-π/2

求证:(sin2x/(1-cos2x))·(sinx/(1+sinx))=tan(π/4-x/2).[sin2x/(1-cos2x)]·[sinx/(1+sinx)]=2sinx*cosx*sinx/[2(sinx)^2*(1+sinx)]

化简sin（2π+x）cos（π-x）sin（π-x）/cos（x-π）sin（-π-x）sin（π+x）原式=[sinx*(-cosx)*sinx]/[(-cosx)*sinx*(-sinx)]=-1

sin(x-π/2)等于cosx还是-cosx1.sin(x-π/2)=-sin（π/2-x）=-cos（x）2.sin(x-π/2)=sin（π-（x-π/2）=sin（π/2-x）=cos（x）哪一个啊,很像都对啊,1.sin(x-π/

sin(x+π/3)用诱导公式化简如题sin(2x+π/3)和3sin(2x+π/3)sin(x+π/3)=sinxcosπ/3+cosxsinπ/3=1/2sinx+√3/2cosx

已知sin(x+π/6)=1/3,求sin(5π/6-x)+sin^2(π/3-x)sin(x+π/6)=1/3sin(5π/6-x)=sin[π-(x+π/6)]=1/3sin^2(π/3-x)=sin^2[π/2-(x+π/6)]=co

已知sin(x+π/6)=1/4,求sin(5π/6-x)+sin^2(π/3-x)sin(5π/6-x)=sin(π-(x+π/6))=sin(x+π/6)=1/4sin(π/3-x)=sin(5π/6-x-π/2)=-cos(5π/6-

∫dx/[a*sin^2(x-π/2)+b*sin(x-π/2)+c]∫dx/[a*sin^2(x-π/2)+b*sin(x-π/2)+c]X从0到2π的积分值a,b,c,为常数LZ好,∫(sin5x)(sin3x)dx=∫1/2[cos(