log2×log5

log2/log5等于多少没底?你题写错了吧。是lg2/lg5吧？补充问题在回答问题有错误

怎样计算（log2)^2+(log5)^2+(2*log2)*log5首先这是个完全平方式,先进行合并（log2)^2+(log5)^2+(2*log2)*log5=(log2+log5)^2然后根据对数函数的性质log2+log5=log

log2[log3[log5125]]=?log2[log3[log5125]]=?log2[log3[log5125]]=log2[log3(3)]=log2(1)=0

(log2)和(log3)变成(log5)要求log5跟log3是没有关系的log5的求法是1-log2也就是log10-log2=log10/2=log5log2大约为0.3010所以log5=1-0.3010=0.6990

log2加log5怎么算?lg2+lg5=lg2×5=lg10=1;如果本题有什么不明白可以追问,log(2)+log(5)=lg10=1

log5[log2(log9/log3)]=?log5[log2(log9/log3)]=log5[log2(2)]=log5(1)=0

(log5)^2+(log2)(log50)=?(log5)^2+(log50)(log2)(log5)^2+(log(5*10))(log2)=(log5)^2+(log5+log10)(log2)=(log5)^2+(log5+1)(l

log2(5)*log5(8)化简log2(5)*log5(8)=log2(5)*log5(2^3)=log2(5)*3*log5(2)=3

(log5)^2+log2·log50常用对数一般用lgN表示.(lg5)^2+lg2*lg50=(lg5)^2+lg(10/5)*lg(10*5)=(lg5)^2+(lg10-lg5)*(lg10+lg5)=(lg5)^2+(1-lg5)

log2(log5x)=-1log2(log5x)=-1log5x=2-¹=1/2x=5^(1/2)x=√5你的意思是log2的底是2，log5底是5吗?那log2和log5就都等于1。因为底数和指数相同。然后你在自己算，我看不到

(log2)^2+(log5)^2+log2*log25(log2)^2+(log5)^2+log2*log25=(log2)^2+(log5)^2+log2*2log5=(lg2+lg5)^2=1

2log510+log50.25=2log525-3log264=log2(log216)=已知lg2=a,lg3=b,求log34,log212已知lg2=a,lg3=b,log34=lg4/lg3=2lg2/lg3=2a/b,log21

 求(log2)^3+(log5)^3+log5×log8的值.你是不是写错了?都没有写底数?一般只有以10和e为底的才能省略(lg2)^3+(lg5)^3+lg5×lg8=(lg2)^3+(lg5)^3+3(lg2)^2×lg5

log25乘log54等于多少log2(5)*log5(4)=log2(5)*2log5(2)=2log2(5)*log5(4)=log2(5)*2log5(2)=2.4217825476303约等于2

log2^5乘以log5^2等于多少?=lg5/lg2xlg2/lg5=1log2^5=lg5/lg2log5^2=lg2/lg5所以log2^5乘以log5^2=1log2^5乘以log5^2log2^5=lg5/lg2log5^2=lg

比较大小log25和log58log2(5)>log2(4)=2log5(8)log2(5)>log5(8)设log25除以log58等于K，将其化为自然对数，则K等于(ln5*ln5)/(ln2*ln8），等于ln25/ln16,所以K大

计算：log2(8)×log4(5)×log5(16)log2(8)×log4(5)×log5(16)=lg8/lg2×lg5/lg4×lg16/lg5=3lg2/lg2×lg5/2lg2×4lg2/lg5约分=3×1/2×4=6log2(

lg8*log2(5)*log5(4)得多少?=lg8*（lg5/lg2）*lg4/lg5=（lg8）*2=（3lg2）*2=6lg2首先：lg8=3lg2，log2(5)=lg5/lg2，log5(4)=lg4/lg5=2lg2/lg5所

log2(5)×log5(8)=3步骤log2(5)×log5(8)=(lg5)/(lg2)×(lg8)/(lg5)=(lg8)/(lg2)=(lg2^3)/(lg2)=3lg2/lg2=3log2(5)×log5(8)=(lg5/lg2)

(log5)+(log2)(log50)的值!急用,谢咯!我觉得应该是lg吧原式=（lg5）+（lg2）（lg（25×2））=（lg5）+（lg2）（lg5+lg2）=（lg5）+（lg2）（2lg5+lg2）=（lg5）+2lg5lg2+