y=1x

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(1-y/x)^2009*(x/(y-x))^2010=((x-y)/x)^2009*(x/(x-y

(1-y/x)^2009*(x/(y-x))^2010=((x-y)/x)^2009*(x/(x-y))^2010=x/(x-y)=1/(1-y/x)=1/(1-9/10x/(x-y)=1/(1-y/x我只是不要明白这不是怎样算出来的请详细

y'/y=1/x

y'/y=1/xdy/dx=y/xdy/y=dx/x同时积分ln|y|=ln|x|+ce为底同时幂次方|y|=|x|+c这就是通解

已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x

已知x/(y+z)+y/(z+x)+z/(x+y)=1求(x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?因为x/y+z+y/z+x+z/x+y=1所以x/y+z=1-y/z+x-z/x+y,两边同乘以x得x^2/y

y'-(1/x)y=xe^-x

y'-(1/x)y=xe^-x典型的y‘-P(x)y=Q(x)的形式,两边同时乘以e^∫P(x)dx就可以了所以这里是乘以e^(∫-1/xdx)=1/x就是(1/x)y'-1/x^2y=e^(-x)就是(y/x)'=e^(-x)两边同时积分

y(x+y)+(x-y)²-(x+y)(x-y),其中x=-1/3,y=3

y(x+y)+(x-y)²-(x+y)(x-y),其中x=-1/3,y=3y(x+y)+(x-y)²-(x+y)(x-y)=xy+y²+x²-2xy+y²-x²+y²=3

(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.

(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.(x-y)(x+y)-(x+y)²+2y(y-x)=(x+y)(x-y-x-y)+2y(y-x)=-2y(x+y)+2y(y-x)=2y(-x-y+y-x)

2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2

2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2x-1=2,x-1=-2x=3,x=-1原式=2xy+y²-(x²-y²+2y²+2xy)=2xy+y²-

x>=1,x-y

x>=1,x-yx>=1,x-y18,用坐标轴画个图就出来了。

y=x-1(x

y=x-1(x是啊,很简单的一个分段函数.当X是,是一个分段函数

X+X+X+Y+Y=20 X+Y+Y=14.6 x=?Y=?速度啊1分钟时间 X+X+X+Y+Y=2

X+X+X+Y+Y=20X+Y+Y=14.6x=?Y=?速度啊1分钟时间X+X+X+Y+Y=20X+Y+Y=14.6x=?Y=?速度啊1分钟时间20错了是25啊3X+2Y=20X+2Y=14.6那么X=2.7Y=5.95

x.y都是自然数,且x(x-u)-y(y-x)+12,求x.y得值快1且x(x-y)-y(y-x)=

x.y都是自然数,且x(x-u)-y(y-x)+12,求x.y得值快1且x(x-y)-y(y-x)=12x(x-y)-y(y-x)=12x(x-y)+y(x-y)=12(x-y)(x+y)=12x^-y^=12x=4;y=2

若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值

若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值2/x-1/y=3(2y-x)/(xy)=3xy/(x-2y)=-1/3{(y/x)-[y/(x-y)]*[(x-y)/x-x+y]}/[(x-2y)/x

已知2x-y=0,求分式【1+(3*y*y*y/x*x*x-y*y*y)】/【1+(2y/x-y)】

已知2x-y=0,求分式【1+(3*y*y*y/x*x*x-y*y*y)】/【1+(2y/x-y)】的值注:x*x*x-y*y*y=(x-y)*(x*x+xy+y*y)这个题lz想太复杂了,y=2x代进去,原式=(1+(24x^3/x^3-

y=[x-1],

y=[x-1],取整应该不是中括号,而是绝对值吧

设x,y满足约束条件x+y>=1,x-y>=-1,2x-y

设x,y满足约束条件x+y>=1,x-y>=-1,2x-y画出x+y>=1,x-y>=-1,2x-y=7*(a^3b^4)^(1/7)(a^3b^4)^(1/7)=7/(a^3b^4)^(1/7)>=7最小值7(a=b)

设x,y满足约束条件x+y>=1,x-y>=-1,2x-y

设x,y满足约束条件x+y>=1,x-y>=-1,2x-y首先救出每两条直线交点,共3个交点,.然后把交点的坐标代入目标函数.根据题目要求即可得出答案.比如本题说只在(1,0)处取得最小值.那么就是(1,0)的值比其它的值都要小.再解出a的

{3(x+y)+3(y+x)=1,3(x+y)+4(y-x)=-1

{3(x+y)+3(y+x)=1,3(x+y)+4(y-x)=-13(x+y)+3(y-x)=1(1)3(x+y)+4(y-x)=-1(2)(2)-(1)得y-x=-2(3)代入(1)3(x+y)-6=1x+y=7/3=>x=7/3-y又由

常微分方程y'=(x+y)ln(x+y)-1

常微分方程y'=(x+y)ln(x+y)-1y'+1=(x+y)ln(x+y)(dy/dx)+1=(x+y)ln(x+y)令u=x+y,那么du/dx=1+(dy/dx)于是上式变为:du/dx=ulnu于是du/(ulnu)=dxd(ln

y'=(x-y+1)/(x+y-3)通解

y'=(x-y+1)/(x+y-3)通解(x+y^2+3)dy=(x-y+1)dx或:xdy+ydx+(y^2+3)dy-(x+1)dx=d(xy)+(y^2+3)dy-(x+1)dx=0通解为:xy+y^3/3+3y-x^2/2-x=C

2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51

2(x+y)-3(x-y)=16(x+y)+(x-y)=512(x+y)-3(x-y)=12x+2y-3x+3y=1-x+5y=16(x+y)+(x-y)=517x+5y=618x=60x=15/2y=17/10第一个式子可化为:5y-x=