(x2+y2)2-4x2y2

(x2+y2)2-4x2y2因式分解(x2+y2)2-4x2y2因式分解=（x²+y²+2xy）(x²+y²-2xy)=(x+y)²(x-y)²如果本题有什么不明白可以追问,(x2

因式分解(x2+y2-a2)2-4x2y2(x2+y2-a2)2-4x2y2=（x²+y²-a²+2xy）(x²+y²-a²-2xy)=[(x+y)²-a²][

4x2y2-(x2+y2)2的答案4x2y2-(x2+y2)2=（2xy-x²-y²）（2xy＋x²+y²）=-(x-y)²(x+y)²4x²y²-（x

分解因式(X2+Y2)2-4X2Y22是平方(x2+y2+2xy)(x2+y2-2xy)=(x+y)2(x-Y)2=(x2-y2)2=x4+y4-2x4y4

(x2+y2-1)-4x2y2因式分解2是平方﹙x²＋y²－1﹚²－4x²y²＝﹙x²＋y²－1－2xy﹚﹙x²＋y²－1＋2xy﹚＝﹙x－y－1﹚﹙

x2+y2-x2y2-4xy-1x²+y²-x²y²-4xy-1=(x²-2xy+y²)-(x²y²+2xy+1)=(x+y)²-(xy+1)

(x2+y2)(x2-xy+y2)-2x2y2因式分解打开,然后再整理,就可以了~(x2+y2)(x2-xy+y2)-2x2y2=x4-x3y+2x2y2-xy3+y4-2x2y2=x4+y4-x3y-xy3=(x-y)(x3-y3)=(x

因式分解x2y2-x2-y2+1原式=4xy-2x-2y+1=2x(2y-1)-(2y-1)=(2x-1)(2y-1)=X2y2-X2-y2+1=X2(y2-1)-(y2-1)=(y2-1)(x2-1)

X2y2-x2-y2+1因式分解.x^2(y^2-1)-(y^2-1)=(x^2-1)(y^2-1)=(x+1)(x-1)(y+1)(y-1)x^2y^2-x^2-y^2+1=x^2(y^2-1)-(y^2-1)=(x^2-1)(y^2-1

已知:x-y=-2求(x2+y2)2-4xy(x2+y2)+4x2y2的值(x2+y2)2-4xy(x2+y2)+4x2y2=(x^2+y^2-2xy)^2=(x-y)^4=(-2)^4=16

已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2=巳知是：(x-2y)的平方+(xy-1)的平方=0,利用非负数的性质得x=2y,且xy=1故y=±√2/2

x2y2-1/4(x2+y2)2以上的2都是二次方x2y2-1/4(x2+y2)2=x2y2-x4/4-x2y2/2-y4/4=-x4/4+x2y2/2-y4/4=-1/4(x4-2x2y2-y4)=-1/4(x2-y2)2=-1/4(x+

(z2-x2-y2)2-4x2y2=?因式分解,题中的“2”均为平方,无乘号.平方差原式=(z²-x²-y²+2xy)(z²-x²-y²-2xy)=[z²-(x²

因式分解（z2-x2-y2）2-4x2y2,用初二知识解答（z²-x²-y²）²-（2xy）²=（z²-x²-y²+2xy）（z²-x²-y

x2y2-x2-y2+4xy+1分解因式x2y2-x2-y2+4xy+1=(xy)^2+2xy+1-(x^2-2xy+y^2)=(xy+1)^2-(x-y)^2=(xy+1+x-y)(xy+1-x+y)

(x2+y2)2-x2y2分解因式那个2是平方(x²+y²)²-x²y²=(x²+y²)²-(xy)²=[(x²+y²)+xy][

分解因式(x2+y2)(x2-2xy+y2)+x2y2注；2为平方(x²+y²)(x²-2xy+y²)+x²y²=(x²+y²)²-2xy(x

因式分解第一题：(1)x3+3x2-4；(2)x4-11x2y2+y2；(3)x3+9x2+26x+24；(4)x4-12x+323因式分解第二题：(1)(2x2-3x+1)2-22x2+33x-1；(2)x4+7x3+14x2+7x+1；

因式分解：（1）36-x2（2）-a2+b2（3）x2-16y2（4）x2y2-z2（1）36-x2=（6+x）(6-x)（2）-a2+b2=(b+a)(b-a)（3）x2-16y2=(x+4y)(x-4y)（4）x2y2-z2=(xy+z

已知x2+4y2+x2y2-6xy+1=0,求x4-y4/2x-y乘2xy-y2/xy-y2除以（x2+y2/xy）2乘1/x+y的值因为x²+4y²+x²y²-6xy+1=0(x²-4xy