3x+(100-x)÷2=100

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x-2x+3x-4x+5x.+99x-100x=25求解

x-2x+3x-4x+5x.+99x-100x=25求解x(1-2+3-4+...+99-100)=25x[(1-2)+(3-4)+...+(99-100)]=25x(-1×50)=25x=25/(-50)=-1/2x-2x+3x-4x+.

2x+3x+4x+5x+x+6x+7x=100

2x+3x+4x+5x+x+6x+7x=1002x+3x+4x+5x+x+6x+7x=10028x=100x=100/28x=25/727x=100x=100/27;;;;;;;;;;;速率可达粉色礼服螺丝钉解放isskl其实我不会2x+3

x+2x+3x+.+100x

x+2x+3x+.+100x原式=(1+2+3+.+99+100)*X=[(1+100)*100/2]*X=5050X第一步到第二步是求和公式,(首项+末项)*项数/2假设x=1,结果为5050

(X+X)+(X-X)+(X*X)+(X/X)=100

(X+X)+(X-X)+(X*X)+(X/X)=100(X+X)+(X-X)+(X*X)+(X/X)=1002X+0+X*X+1=1002X+X*X=99X(X+2)=99X=9因为(9+9)+(9-9)+(9×9)+(9÷9)=100,∴

解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x)

解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x)2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...

1X+2X+3X…+98X+99X+100X=50500X X等于多少?

1X+2X+3X…+98X+99X+100X=50500XX等于多少?1X+2X+3X…+98X+99X+100X=5050x=50500x=10X=01X+2X+3X…+98X+99X+100X=5050X,又=50500X,消去X,50

1x+2x+3x+4x+5x+6x+7x…+99x=100

1x+2x+3x+4x+5x+6x+7x…+99x=100 

100×2x+10x+3x+216=100×3x+10×2x+x

100×2x+10x+3x+216=100×3x+10×2x+x100×2x+10x+3x+216=100×3x+10×2x+x200x+10x+3x+216=300x+20x+x216=321x-213x108x=216x=2

解方程:x-2x+3x-4x+...+99x-100x=25

解方程:x-2x+3x-4x+...+99x-100x=25x-2x+3x-4x+...+99x-100x=25(x-2x)+(3x-4x)+……+(99x-100x)=25-x-x-……-x=25-50x=25x=25÷(-50)x=-0

解方程:x-2x+3x-4x+.+99x-100x=25

解方程:x-2x+3x-4x+.+99x-100x=25x-2x+3x-4x+.+99x-100x=25(x-2x)+(3x-4x)+.+(99x-100x)=25-x-x-……-x=25-50x=25x=-1/2

x-2x+3x-4x+...+99x-100x=25

x-2x+3x-4x+...+99x-100x=25x-2x+3x-4x+...+99x-100x=25(1-2)x+(3-4)x+…+(99-100)x=25-x-x-…-x=25-50x=25x=-1/2

已知x^4+x^3+x^3+x^2+x^1+1=0,求x^100+x^99+x^98+x^97+x^

已知x^4+x^3+x^3+x^2+x^1+1=0,求x^100+x^99+x^98+x^97+x^96的值x^4+x^3+x^2+x+1=0,x^100+x^99+x^98+x^97+x^96=x^96(x^4+x^3+x^2+x+1)=

先化简再求值(x+3x+5x+7x+.+101x)-(2x+4x+6x+...100x),其中x=5

先化简再求值(x+3x+5x+7x+.+101x)-(2x+4x+6x+...100x),其中x=51分之2=x+(3x-2x)+(5x-4x)+……+(101x-100x)=x+x+……+x=51x=51×2/51=2

X+X+13+[100-(x+13)÷2-X]×3=200

X+X+13+[100-(x+13)÷2-X]×3=200X+X+13+[100-(x+13)÷2-X]×3=2002X+13+300-3(X+13)÷2-3X=2002X-3X/2-3X+13+300-39/2=2003X+3X/2-2X

f(x)=x(x-1)(x+2)(x-3)(x+4)……(x+100),求f'(1)

f(x)=x(x-1)(x+2)(x-3)(x+4)……(x+100),求f'(1)f'(x)=[x'(x-1)(x+2)(x-3)(x+4).(x+100)]+[x(x-1)'(x+2)(x-3)(x+4).(x+100)]+...+[x

已知x^4+x^3+x^2+x^2+1=0,求x^100+x^99+x^98+x^97+x^96的值

已知x^4+x^3+x^2+x^2+1=0,求x^100+x^99+x^98+x^97+x^96的值见上因为x^4+x^3+x^2+x^2+1=0所以x^100+x^99+x^98+x^97+x^96=x^96(x^4+x^3+x^2+x^

1/2x-8 x+3x+(1/2x-8)=100 x=?

1/2x-8x+3x+(1/2x-8)=100x=?1/2x-8x+3x+(1/2x-8)=100-4x=108x=27

1/2x-8 x+3x+(1/2x-8)=100 =x?

1/2x-8x+3x+(1/2x-8)=100=x?先化简:0.5x+0.5x-8x+3x=108-4x=108x=-27

已知x^4+x^3+x^2+x+1=0,求x^100+x^99+x^98+x^97+x^96的值.

已知x^4+x^3+x^2+x+1=0,求x^100+x^99+x^98+x^97+x^96的值.提公因式x^96,得:原式=x^96*(x^4+x^3+x^2+x+1)=x^96*0=0

已知x^4+x^3+x^2+x+1=0,求x^100+x^99+x^98+x^97+x^96的值

已知x^4+x^3+x^2+x+1=0,求x^100+x^99+x^98+x^97+x^96的值提公因式x^96,得:原式=x^96*(x^4+x^3+x^2+x+1)=x^96*0=00