y=ln(1+x3)的微分

求y=[ln(1-x)^2]^2的微分y=[ln(1-x)^2]^2y'=2[ln(1-x)^2]*[ln(1-x)^2]'=2[ln(1-x)^2]*[2ln(1-x)]'=2[ln(1-x)^2]*2*1/(1-x)=4*[ln(1-x

y=ln平方（1-x)的微分y=d[ln²(1-x)]/dx=2ln(1-x)*d[ln(1-x)]/dx=2ln(1-x)*1/(1-x)*d(1-x)/dx=2ln(1-x)/(x-1)

求函数y=ln²2x的微分y=(ln2x)^2因为y'=[(ln2x)^2]'[ln2x]'[2x]'=[2ln(2x)][1/2x][2]=[2ln(2x)]/x所以dy=[[2ln(2x)]/x]dxy'=[2ln(2x)]/

求函数的微分Y=ln(lnx)1/(xlnx)

z=ln(x^2+y^2)的全微分f(x,y)全微分就是两个偏导数分别乘以微分之和.dz=f'x(x,y)dx+f'y(x,y)dy=(2x/(x²+y²))dx+(2y/(x²+y²))dy(2x/

y＝lnsin(2x-1)的微分谢谢看图：~如果您认可我的回答,请及时点击【采纳为满意回答】按钮~~手机提问者在客户端上评价点【满意】即可~~~您的采纳是我前进的动力~~~如还有问题,可以【追问】~~~祝学习进步,更上一层楼!O(∩_∩)O

y=ln√(1-sinx)/(1+sinx)求微分.y=(1/2)[ln(1-sinx)-ln(1+sinx)]故y`=(1/2)[(-cosx)/(1-sinx)-(cosx)/(1+six)y`=(-1/2)[(2cosx)/(1-(s

设xy-ln(y+1)=0求微分dyxy-ln(y+1)=0xy=ln(y+1)哎,算了.电脑打这个也太痛苦了xy-ln(y+1)=0,ydx+xdy-dy/(y+1)=0,[x-1/(1+y)]dy=-ydx,dy=y(1+y)dx/[1

Y=ln(4X+1)求微分dydy=1/(4x+1)*(4x+1)'dx=4/(4x+1)dxy'=4/(4x+1)ordy=4dx/(4x+1).

y=ln[(1-x)^2]求其微分,dy=d（ln[(1-x)^2]）=d[（1-x）²]/(1-x)²=2（1-x）d（1-x）/（1-x）²=2（x-1）dx/（1-x）²dy={ln[(1-x)

y=ln根号（1-x^2）求微分y=ln根号（1-x^2）求微分ln根号下（1-x∧2）的导数为-x/(1-x∧2).

4、求y=2分之1ln(1+x的平方)的微分dydy=1/2d[ln(1+x^2)]=1/[2(1+x^2)]d(1+x^2)=1/[2(1+x^2)]2xdx=x/(1+x^2)dxdy=1/2(1/(1+x^2)(2)dx=(1/(1+

已知y=ln(1+x^2),在x=1处的微分dy=dy=(2x)/(1＋x²)则：dy|(x=1)=1

y=arctan(x/3)+ln(1-x),函数的微分dy=?y'=1/(1+(x/3)^2)+1/(1-x)乘以(-1)=9/(x^2+9)+1/(x-1)

二元函数z=cos3xy+ln(1+x+y)的全微分dz=dz=[-3ysin3xy+1/(1+x+y)]dx+[-3xsin3xy+1/(1+x+y)]dy第一换元法d(x²-1)=2xdx∫x√(x²-1)dx=[∫

二元函数z=cos3xy+ln(1+x+y)的全微分dz=?z偏x=-sin3xy*3y+1/(x+y+1)z偏y=-sin3xy*3x+1/(x+y+1)dz=[-sin3xy*3y+1/(x+y+1)]dx+[sin3xy*3x+1/(

y=ln根号下1+sinx/1-sinx的微分y=1/2ln(1+sinx)-1/2ln(1-sinx)y'=1/2×1/(1+sinx)×cosx-1/2×1/(1-sinx)×(-cosx)=1/2×[cosx/(1+sinx)+cos

求y=ln(x^2+根号下(x^2+1))的微分y'=1/(x+根号下x^2+1)*(x+根号下x^2+1)'=1/(x+根号下x^2+1)*(1+x/根号下x^2+1)=1/(x+根号下x^2+1)*(根号下x^2+1+x)/根号下x^2

求函数的微分y=ln²（1-2x）解y=ln²(1-2x)y'=dy/dx=[ln²(1-2x)]'=2ln(1-2x)[ln(1-2x)]'(1-2x)'=2ln(1-2x)[1/(1-2x)(-2)=[-4

求y=ln√1-x^3的微分如题.y=ln√(1-x³)=(1/2)ln(1-x³)dy/dx=(1/2)*1/(1-x³)*(-3x²)=-3x²/[2(1-x³)]=3x