x3sin2xx4+2x2+1

计算(x3+x2+x+2)/(x2+1)(x3+x2+x+2)/(x2+1)=(x3+x+x2+1+1)/(x2+1)=x+1+1/(x2+1)【OK?】请给出具体的值。。。

4x2-(x2+1)2因式分解4x^2-x^4-2x^2-1-x^4+2x^2-1-(x^2-1)^2-(x+1)^2(x-1)^24x²-(x²+1)²=(2x+x²+1)(2x-x²-1

(1/2)不等式x2解若X≧4,原方程化为x²-2x+8选B讨论绝对值总算式的正负号，然后根据正负号脱去绝对值再求解。≥≤具体过程是：若2X-8>0解得X>4，此时可以直接去掉绝对值即得：x²若2X-8≤0解得X≤4，此

解方程：X2--1/8(X2+2X)+X2+2X/3(X2--1)=11设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8

∫x2/(1+x2)2dx求不定积分?要快~∫x2/[(1+x2)2]dx(-(x/(1+x^2))+ArcTan[x])/2∫x²/(1+x²)²dx=(-1/2)∫xd[1/(1+x²)]分部积分

y=x+√(1-x2)y2=x2+(1-x2)+2x√(1-x2)2x√(1-x2)≤x2+1-x2来源于{x-√(1-x2)}^2≥0x^2-2x√(1-x2)+(1-x2)≥0x^2+(1-x2)≥2x√(1-x2)

已知x2－4x+1=0,求x2／(x2)2－3x2+1x2－4x+1=0两边同除以xx-4+(1/x)=0x+(1/x)=4(x+(1/x))^2=4^2=16x^2+(1/x^2)=16-2=14x2／[(x2)2－3x2+1]=1/[x

2^5+5x2^4+10x2^3+10x2^2+5x2+1=32+5*16+10*8+10*4+10+1=32+80+80+40+10+1=32+200+11=243帮到你的话请采纳哦!

解方程2/(x2-x)+6/(1-x2)=7/(x2+x)x2为的平方2/(x2-x)+6/(1-x2)=7/(x2+x)2/x(x-1)-6/(x-1)(x+1)=7/x(x+1)[x*(x-1)*(x+1)]*[2/x(x-1)-6/(

已知X1+x2+X2+...+Xn=1,证明不等式：X1^2/（X1+X2）+X2^2/(X2+X3)+X3^2/(X3+X4)+.+Xn^2/(Xn+X1)>=1/2X1、X2、X3、...、Xn是正数解答如下:证法一：均值不等式.X1^

已知X1+x2+X2+...+Xn=1,证明不等式：X1^2/（X1+X2）+X2^2/(X2+X3)+X3^2/(X3+X4)+.+Xn^2/(Xn+X1)>=1/2是否应加个条件：X1、X2、X3、...、Xn是正数.证法一：均值不等式

y=3x/1+x2的值域1-X2/1+X2→2-(X2+1)/1+X2→-1+2/(1+X2)这一步怎么得到的,1-X2/1+X2到-(X2-1)/1+X2到-X2-1+2/1+X2到2-(X2+1)/1+X2到2/(1+X2)-X2+1/

若x2-3x+1=0,求（2x2×x3-5x2×x2+2x3-8x2）÷（x2+1）的值

x2+(x+1)2+x2(x+1)2因式分解x²+(x+1)²+x²(x+1)²因式分解原式=x²+x²+2x+1+(x+x²)²=1+2(x²+x)

(1/2)^3x2^3与(1/2x2)^3（1/2）^3x2^3=1/2x1/2x1/2x2x2x2=（1/2x2）x（1/2x2）x（1/2x2）=1x1x1=1^3=（1/2x2）^3

2/1x2/1x2/1=（）=（）=1/4x1/2=1/8

因式分解(x2+2x)2+2x2+4x+1(x^2+2x)^2+2x^2+4x+1=(x^2+2x)^2+2(x^2+2x)+1=(x^2+2x+1)^2=(x+1)^4(x²+2x)²+2x²+4x+1=(x

2x2+1+2+3+2x2==4+1+2+3+4=14

(x2+1)2-4x(x2-1)因式分解(x^2+1)^2-4x(x^2-1)=(x^2-1)^2-4x(x^2-1)+4x^2=[x^2-1-2x]^2

2(x2+1/x2)-9(x+1/x)+14=令a=x+1/xa²=x²+2+1/x²2(a²-2)-9a+14=0(2a-5)(a-2)=0x+1/x=5/22x²-5x+2=0(2x-1