極限n^2*((n^2+3)/(n^2-3))^0.5-n^2

证明不等式：(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n先证明对于任意x≠0,1+xf(0)=1>0,即1+x因e-（n-1）+e-（n-2）+…+e-1+1=1-e^-n/1-e^-1＜1/1-e^-1=e/(e-1

[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简原式=(3n²+3n+2n²-3n²+n+6n²+12n)/6=(2n²+6n²+16n)/6=(n²+

[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简分子是6还是6+n(n+2)

化简n分之n-1+n分之n-2+n分之n-3+.+n分之1(n-1)/n=1-1/n各项都可以这么化那么S=(n-1)/n+(n-2)/n+(n-3)/n+……[n-(n-1)]/n=(1-1/n)+(1-2/n)+(1-3/n)+……+[

化简n分之n-1+n分之n-2+n分之n-3+.+n分之1(1+2+3+.+n-1)/n=(1+n-1)*(n-1)/2/n=(n-1)/2看不懂,就写两个上面的式子,把两个加起来,记得要前后相加,就是(n-1)/n+1/n

-2n+n^2+n^3还能化简吗?-2n+n^2+n^3还能化简吗?不能.还可以提公因式：=n（n^2+n-2）=n（n+2）（n-1）希望对你有帮助，满意请及时采纳，你的采纳是我回答的动力！-2n+n^2+n^3=n（n^2+n-2）=n

-n^3+8n^2-16n-n(n-4)^2

化简(n+1)(n+2)(n+3)设n+2=x所以(n+1)(n+2)(n+3)=(x-1)*x*(x+1)=(x^2-1)*x=x^3-x将n+2=x代入,得n^3+3n^2*2+3n*2^2+2^3-n-2=n^3+6n^2+12n-n

3(n-1)(n+3)-2(n-5)(n-2)3(n-1)(n+3)-2(n-5)(n-2)=3(n^2+2n-3)-2(n^2-7n+10)=n^2+20n-29如果不懂,祝学习愉快!

2^n*3^n*5^n+2/30^n=2^n×3^n×5^n×5²/(2×3×5)^n=2^n×3^n×5^n×5²/2^n×3^n×5^n=5²=25

lim(n+3)(4-n)/(n-1)(3-2n)上下除以n²原式=lim(1+3/n)(4/n-1)/(1-1/n)(3/n-2)=(1+0)(0-1)/(1-0)(0-2)=1/2

lim(n^3+n)/(n^4-3n^2+1)lim(n^3+n)/(n^4-3n^2+1)=lim(1/n+1/n^3)/(1-3/n^2+1/n^4)=(0+0)/(1-0+0)=0

lim2^n+3^n/2^n+1+3^n+1n是趋向于无穷吗?如果是的话,就上下除以最大的数,上下除以3的n+1次方,然后化简得五分之一

n(n+1)(n+2)(n+3)+1因式分解n(n+1)(n+2)(n+3)+1=(n²+3n)(n²+3n+2)+1=(n²+3n)²+2(n²+3n)+1=(n²+3n+1)&

lim[(n+3)/(n+1))]^(n-2)【n无穷大】lim[(n+3)/(n+1)]^(n-2)=lim[1+2/(n+1)]^(n-2)=lim{[1+2/(n+1)]^[(n+1)/2]}^[(n-2)×2/(n+1)]=lime

lim(2^n+3^n)^1\n(n趋向无穷)

n(n+1)(n+2)(n+3)+1等于多少(n^2+n)(n^2+5n+6)+1=n^4+6n^3+11n^2+6n+1(n^2+n)(n^2+5n+6)+1=n^4+6n^3+11n^2+6n+1

级数n/(n+1)(n+2)(n+3)和是多少n/(n+1)(n+2)(n+3)=(n+1-1)/(n+1)(n+2)(n+3)=1/(n+2)(n+3)-1/(n+1)(n+2)(n+3)=[1/(n+2)-1/(n+3)]-(1/2)[

n*1+n*2+n*3+n*4.求公式等比数列的前n项合a1是首项,即n^1q是公比,即每相邻两项的比,即n这就是一个等比数列求和啊，通项公式就是n的平方啊

求最小值((n+2)(n+4))/(n(n+3))等图.