minS=4X1 5X1 6X3
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线性规划(要解题过程)答案我知道mins=2x1+x2+x3{2X1-X2+X3=2①约束条件{x1+x3=2②{x1,x2,x3>=0③有哪些可行基?写出它们对应的单纯形表.2楼说的对,是运筹学的作业。晕,200分悬赏都没有知道~~~~就
x1+5x2+2x3-4x4=3-3x1-2x2+3x3+4x4=-6-x1+3x2-x3-4x4=-2-2x1+6x2+4x3+4x4=-52x1+13x2+3x3-12x4=4x是英文字母解:系数矩阵=2135-51114-33156-
解线性方程组x1+x2+3x3+4x4=52x1+4x2+4x3+6x4=8-x1-2x2-x3-2x4=-3K(-1,0,-1,1)+(2,0,1,0)你的方程组有四个变量,但只有三个方程,没办法解啊!除非有限制条件!
2X1-4X2+5X3+3X4=03X1-6X2+4X3+2X4=04X1-8X2+17X3+11X4=0解以上线性方程组系数矩阵=2-4533-6424-81711r2-r1,r3-2r12-4531-2-1-10075r1-2r2007
求解线性方程组X1+X2+X3=62X1+3X2+X3=11X1-X2+2X3=5X1=1X2=2X3=3
解线性方程组x1-x2-x3=2x1+x2+4x3=03x1+5x3=3x1-x2-x3=2(1)x1+x2+4x3=0(2)3x1+5x3=3(3)(1)+(2)得2x1+3x3=2(4)(4)×3得6x1+9x3=6(5)(3)×2得6
{2X1-X2+3X3=33X1+X2-5X3=04X1-X2+X3=3X1+3X2-13X3=-6{X1-2X2+3X3-4X4=4X2-X3+X4=-3X1+3X2-3X4=1-7X2+3X3+X4=-3第一题X1=1X2=2X3=1你
已知数据3,x1,2,4,x2,5,x3,6的平均数是5,那么x1+x2+x3=.X1+X2+X3=8×5-3-2-4-5-6=20
2X1+X2-X3+X4=13X1-2X2+X3-3X4=4X1+4X2-3X3+5X4=-2X1+X2+X3+X4=0X1+2X2+4X3+4X4=02X1+3X2+5X3+5X4=01题:对增广矩阵进行行变换原方程组无解.2题:对系数矩
线性方程组求解2x1-x2+3x3=33x1+x2-5x3=04x1-x2+x3=3x1+3x2-13x3=-6三元方程用三条方程即可解出:2x1-x2+3x3=3①3x1+x2-5x3=0②4x1-x2+x3=3③3*①-2*②得-5x2
线性方程组求解2x1-x2+3x3=33x1+x2-5x3=04x1-x2+x3=3x1+3x2-13x3=-6用矩阵的方法增广矩阵=2-13331-504-11313-13-6r3-2r1,r2-r1-r4,r1-2r40-729150-
矩阵线性方程组2x1-x2+3x3=33x1+x2-5x3=04x1-x2+x3=3x1+3x2-13x3=-6用消元法怎么计算呢.请需要帮助.个人觉得消元法其实就是使用矩阵的初等变换,你想啊,初等变换到最后为阶梯型矩阵或最简矩阵(就是能消
maxZ=2X1+4X2-5X3X1+X2+X3=72X1-3X2+X3≥10X1.X2.X3≥0maxZ=2X1+4X2-5X3X1+X2+X3=7X1.X2.X3≥0x3=02X1-3X2≥10X1+X2=7maxZ=2X1+4X2x1
解线性方程组x1+2x2+3x3+4x4=52x1+4x2+4x3+6x4=8-x1-2x2-x3-2x4=-3用矩阵1234524468-1-2-1-2-3行变换变成120120011100000设x2=k1,x4=k2,则通解为x1-2
解线性方程组x1+2x2+3x3+4x4=52x1+4x2+4x3+6x4=8-x1-2x2-x3-2x4=-3x1+2x2+3x3+4x4=5(1)2x1+4x2+4x3+6x4=8(2)-x1-2x2-x3-2x4=-3(3)(1)+(
解非齐次线性方程组:2X1-4X2+5X3+3X4=73X1-6X2+4X3+2X4=74X1-8X2+17X3+11X4=21X1-2X2+13X3+9X4=142X1-4X2+5X3+3X4=73X1-6X2+4X3+2X4=74X1-
求齐次线性方程组:2X1-4X2+5X3+3X4=03X1-6X2+4X3+2X4=04X1-8X2+17X3+11X4=0基础解系和通解.得到等价方程组为:x1=2x2+2/7x4;x2=x2;x3=-5/7x4;x4=x4.所以方程组的
2X1+X2-5X3+X4=8,X1-3X2-6X4=9,2X2-X3+2X4=-5,X1+4X2-7X3+6X4=0.求这个方程组的解X1=3,X2=-4,X3=-1,X4=1.Matlab语句就是A=solve('2*X1+X2-5*X
解方程组x1+x2=4,x2+x3=-6,x3+x1=2x1+x2=4①x2+x3=6②x3+x1=2③得x2-x1=4④④+①得2x2=4x2=2代入①得x1=2x1=2代入③得x3=0所以x1=2x2=2x3=0
写出对偶规划X1+5X2-3X3>=15-5X1-6X2+10X3目标函数是什么?