(x的平方+3x)的平方-(x-1)的平方 因式分解

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(x的平方+3x)的平方-(x-1)的平方 因式分解

(x²+3x)²-(x-1)²
=(x²+3x+x-1)(x²+3x-x+1)
=(x²+4x-1)(x²+2x+1)
=[(x+2)²-3](x+1)²
=(x+2+√3)(x+2-√3)(x+1)²

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x^2(x+3)^2-(x-1)^2
=(x^2+3x-x+1)(x^2+3x+x-1)
=(x^2+2x+1)(x^2+4x-1)
=(x+1)^2(x^2+4x-1)

﹙x²+3x﹚²-﹙x-1﹚²
=﹙x²+3x-x+1﹚﹙x²+3x+x-1﹚
=﹙x²+2x-1﹚﹙x²+4x-1﹚

(x²+3x)²-(x-1)²
=(x²+3x+x-1)(x²+3x-x+1)
=(x²+4x-1)(x²+2x+1)
=[(x+2)²-5](x+1)²
=(x+2+√5)(x+2-√5)(x+1)²

正确答案: